Evaluate the surface integral. s zds S is the surface x = y + 2z 2
Question:
Evaluate the surface integral.
∫∫s zds S is the surface x = y + 2z2, 0 ≤ y ≤ 1,0 ≤ z ≤ 1
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To evaluate the surface integral we can first parameterize the surface S Lets substitute x y 2z2 int...View the full answer
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Saud Ur Rehman
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