In contrast to the proof in Exercise 81, we now use coordinates and position vectors to prove

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In contrast to the proof in Exercise 81, we now use coordinates and position vectors to prove the same result. Without loss of generality, let P(x1, y1, 0) and Q(x2, y2, 0) be two points in the xy-plane and let R(x3, y3, z3) be a third point, such that P, Q, and R do not lie on a line. Consider ΔPQR.

a. Let M1 be the midpoint of the side PQ. Find the coordinates of M1 and the components of the vectorRM|-

b. Find the vector OZ, from the origin to the point Z1 two-thirds of the way along

c. Repeat the calculation of part (b) with the midpoint M2 of RQ and the vectorto obtain the vector

d. Repeat the calculation of part (b) with the midpoint M3 of PR and the vector to obtain the vector

e. Conclude that the medians of ΔPQR intersect at a point. Give the coordinates of the point.

f. With P(2, 4, 0), Q(4, 1, 0), and R(6, 3, 4), find the point at which the medians of ΔPQR intersect.

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Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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