Sometimes for z very, very close to the disk, the third term in Equation (6) is so
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Sometimes for z very, very close to the disk, the third term in Equation (6) is so small that it can be dismissed. Show that the electric field is constant for this case.
Transcribed Image Text:
V = k₁ (R - z z+ 2R (6)
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The given equation is V kR z z 2R Lets focus on the third term which is z 2R The problem ...View the full answer
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Related Book For
Calculus With Applications
ISBN: 9780321831101
10th Edition
Authors: Margaret L Lial, Raymond N Greenwell, Nathan P Ritchey
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