A ball is thrown from a point 2m above horizontal ground. The initial speed is 20 ms
Question:
A ball is thrown from a point 2m above horizontal ground. The initial speed is 20 ms-1 and the angle of elevation is 45°. Find the horizontal distance covered when the ball is 12m above the ground.
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16m Explanation The horizontal distance covered by the ball can be calculated using the equation x v2g sin2 where v is the initial velocity g is the acceleration due to gravity and is the angle of elevation Since the ball is thrown from a height of 2m and is 12m above the ground when it reaches its apex we can calculate ...View the full answer
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Related Book For 
Cambridge International AS & A Level Further Mathematics Coursebook
ISBN: 9781108403375
1st Edition
Authors: Lee Mckelvey, Martin Crozier
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