The voltage drop across an electrical resistor is 10 volts and the current through it is 1 ampere. The total heat capacity of the resistor is 20 J/K, and heat is dissipated from the resistor to the surrounding air according to the relation 

where T_am is the ambient air temperature, 25°C; T is the temperature of the resistor; and h, the heat transfer coefficient, is equal to 0.2 J/(K s). Compute the steadystate temperature of the resistor, that is, the temperature of the resistor when the energy loss from the resistor is just equal to the electrical energy input.

Transcribed Image Text:

Q=-h(T-Tam)