In the matrix representation the species \(n\) chosen for elimination is usually referred to as the solvent. The choice of "solvent" species is arbitrary, but it can have an effect on the coefficient and the structure of the resulting form as shown below.

A system with a very large variation in binary diffusion values was studied by Wesselingh and Krishna (2000). The three components are hydrogen (1), nitrogen (2), and dichlorodifluoromethane (3).

Estimate the binary pair values from Eq. (1.53).

Find the \(K\) matrix if species (3) is the solvent. Also show that the \(K\) matrix has different values if species (2) is the solvent.

Although the three matrices look different, show that the eigenvalues are the same. Also show that the component fluxes calculated are the same.

Transcribed Image Text:

DAB 1.8583 x 10-773 == T (MA+ MB) POR DAB (1.53)