Isocyanic acid ( \(\mathrm{HNCO}\) ) can be prepared by heating sodium cyanate in the presence of solid oxalic acid according to the equation

\(2 \mathrm{NaOCN}(s)+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(s) \longrightarrow 2 \mathrm{HNCO}(l)+\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(s)\)

Upon isolating pure \(\mathrm{HNCO}(l)\), an aqueous solution of \(\mathrm{HNCO}\) can be prepared by dissolving the liquid \(\mathrm{HNCO}\) in water. What is the \(\mathrm{pH}\) of a \(100 .-\mathrm{mL}\) solution of HNCO prepared from the reaction of \(10.0 \mathrm{~g}\) each of \(\mathrm{NaOCN}\) and \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), assuming all of the \(\mathrm{HNCO}\) produced is dissolved in solution? \(\left(K_{\mathrm{a}}ight.\) of \(\mathrm{HNCO}=1.2 \times 10^{-4}\).)