Find the equilibrium constant at 298 K for the reaction. The K f for [Cu(NH 3 )

Question:

Find the equilibrium constant at 298 K for the reaction.2 [Cu(NH3)2](aq) = [Cu(NH3)4]+ (aq) + Cu(s)

The Kf for [Cu(NH3)2]+ = 6.3 * 1010 and the rest of the data needed are in Appendix II.Formula Ka, HCH302 1.8 x 10-5 Acetylsalicylic HC9H/O4 3.3 x 10-4 HC6H8O4 3.9 x 10-5 3.9 x 10-6 HAsO 4 5.5 x

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: