How does the approximate root mean square velocity of neon compare to that of krypton at the
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How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?
(a) The root mean square velocity of Ne is approximately four times that of Kr.
(b) The root mean square velocity of Ne is approximately two times that of Kr.
(c) The root mean square velocity of Ne is approximately one-half that of Kr.
(d) The root mean square velocity of Ne is approximately one-fourth that of Kr.
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