The previous exercise shows how the first-order integrated rate law is derived from the first-order differential rate
Question:
The previous exercise shows how the first-order integrated rate law is derived from the first-order differential rate law. Begin with the second-order differential rate law and derive the second-order integrated rate law.
Previous Exercise
The first-order integrated rate law for the reaction A → products is derived from the rate law using calculus:
The equation just given is a first-order, separable differential equation that can be solved by separating the variables and integrating:
In the integral just given, [A]0 is the initial concentration of A.
We then evaluate the integral:
Use a procedure similar to the one just shown to derive an integrated rate law for a reaction A → products, which is onehalf order in the concentration of A (that is, Rate = k[A]1/2).
Use the result from part a to derive an expression for the halflife of a one-half-order reaction.
Step by Step Answer: