Boron forms a series of compounds with hydrogen, all with the general formula B x H y If 0 148 g of one of these compounds gives 0 422 g of B 2 O 3 when burned in excess O 2 , what is its empirical formula X B Hy(s) excess O(g) 2 Y BO3(s) s) 2 1 201 HO(g)...

To determine the empirical formula of the compound you need to find the ratio of the moles of boron ...

Boron forms a series of compounds with hydrogen, all with the general formula B x H y

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Boron forms a series of compounds with hydrogen, all with the general formula B_xH_y. X B Hy(s) + excess O(g) 2 Y BO3(s) + s) + 2/1/201 HO(g)

If 0.148 g of one of these compounds gives 0.422 g of B₂O₃ when burned in excess O₂, what is its empirical formula?

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Chemistry And Chemical Reactivity

ISBN: 9780357001172

10th Edition

Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

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Question Posted: Oct 16, 2023 03:41 AM

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Boron forms a series of compounds with hydrogen, all with the general formula B x H y

Question:

X B Hy(s) + excess O₂(g) → 2 Y B₂O3(s) + s) + 2/1/201 H₂O(g)

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Chemistry And Chemical Reactivity

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