A sample of 0.1687 g of an unknown monoprotic acid was dissolved in 25.0 mL of water

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A sample of 0.1687 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.1150 M NaOH. The acid required 15.5 mL of base to reach the equivalence point.

(a) What is the molecular weight of the acid?

(b) After 7.25 mL of base had been added in the titration, the pH was found to be 2.85.What is the K_a for the unknown acid?

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Chemistry The Central Science

ISBN: 978-0321696724

12th edition

Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward

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Question Posted: Jun 22, 2020 06:59 AM

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A sample of 0.1687 g of an unknown monoprotic acid was dissolved in 25.0 mL of water

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a The molecular weight of the acid can be determined by using the formula Molarity acid Molarity ...View the full answer

Chemistry The Central Science

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