A 70.0-kg worker jumps stiff-legged from a height of 1.00 m onto a concrete floor. (a) What is the magnitude of the impulse he feels on landing, assuming a sudden stop in 8.00 ms? (b) What is the average force?
THINKING IT THROUGH. The impulse is Favg Δt, which cannot be calculated directly from the given data. But the impulse is equal to the change in momentum,
Favg Δt = Δp = mv − mvo. So the impulse can be calculated from the difference in momenta if vo is found.