Question: Translate the following into IA64 code making use of predication. for (i = 0; i < 100: i++) { if (X [i] = Y[i]) }

Translate the following into IA64 code making use of predication. 

for (i = 0; i < 100: i++) { if (X [i] = Y[i]) } Y[i] else X [i] = Y [i] + X [i] 1; 1;

for (i = 0; i < 100: i++) { if (X [i] = Y[i]) } Y[i]Y[i] + else X [i] = X [i] 1; 1;

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