Determine the invariants, and principal values and directions of the following matrices. Use the determined principal directions

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Determine the invariants, and principal values and directions of the following matrices. Use the determined principal directions to establish a principal coordinate system, and following the procedures in Example 1.3, formally transform (rotate) the given matrix into the principal system to arrive at the appropriate diagonal form.

a. 1 1 -1 001 -1 0 1 0

b. -2 1 0 1 1 -2 0 0 0 0

c.-1 1 0 1 -1 0 0 00

d. 6 -3 -3 6 0 0 0] 0 6

Data from example 1.3

Determine the invariants and principal values and directions of the following symmetric second- order tensor

Equation 1.6.3

la = aii= a11 + a22 +933 Ila = 1 Cavity (ajajj - aijaij) = IIIa = det[aij] all a21 a12 922 + 922 a23 a32 a33

For the 2 = 5 root, Eq. (1.6.1) gives the system -3n) = 0 -3n (1) -2ny +4n = 0 4ny) - 8n) = 0 (2) which gives

Equation 1.61

dijn; = ; aina12n2 + a13n3 = a21n1 + a22m2 + a23n3 = a31n a32n2 + az33n3 =  n2

Fig 1.3

X2 n(2) X3 n(1) n(3) 1 X3 X 2

Equation 1.41

(fx x) so0 = !!

Equation 1.51

da, zero order (scalar) d; = Qipap, first order (vector) dj = lip liqapq, second order (matrix) d'ijk =

This result then validates the general theory given by relation (1.6.4), indicating that the tensor should take on diagonal form with the principal values as the elements.  Only simple second-order tensors lead to a characteristic equation that is factorable, thus allowing solution by hand calculation. Most other cases normally develop a general cubic equation and a more complicated system to solve for the principal directions. Again, particular routines within the MATLAB package offer convenient tools to solve these more general problems. Example C.2 in Appendix C provides a simple code to determine the principal values and directions for symmetric second-order tensors.

Equation 1.6.4

dij = 1 0 0 0 2 03 0 0

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