Using polar coordinates and the basic results of Exercise 9.6, formulate the torsion of a cylinder of

Question:

Using polar coordinates and the basic results of Exercise 9.6, formulate the torsion of a cylinder of circular section with radius a, in terms of the usual Prandtl stress function. Note for this case, there will be no warping displacement and ∅ = ∅(r). Show that the stress function is given by:

2  (203)

and the only non-zero stress simplifies to τ,θz = μαr. Check these results with the solution given for the elliptical section for the case with a = b.

Data from exercise 9.6

We wish to reformulate the torsion problem using cylindrical coordinates. First show that the general form of the displacements can be expressed as ur = 0, uθ = αrz, uz = uz(r,θ). Next show that this leads to the following strain and stress fields:

er = eg=e = ere = 0, erz 1 duz 2 dr' duz or=000 = Tro= 0 Trz = . r egz = 1/2 ( ar + a1 ap 182 - + + ar rr 00

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: