Question: [23] Show that if log 1/ Pr(D|H) + log 1/P(H) = K(D|H) + K(H) + O(1), then H is P-random up to K(Pr(|H)) K(P)

[23] Show that if log 1/ Pr(D|H) + log 1/P(H) = K(D|H) +

K(H) + O(1), then H is P-random up to K(Pr(·|H)) − K(P) + O(1), and D is Pr(·|H)-random up to K(P) − K(Pr(·|H)) + O(1). (Negative randomness deficiencies correspond to 0.)

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