A freighter is moving at a speed of 8 knots when its engines are suddenly stopped. (1) If it takes 10 minutes for the freighter to reduce its speed to 4 knots, determine and plot the distance \(s\) in nautical miles moved by the ship and its speed \(v\) in knots as functions of the time \(t\) during this interval. The deceleration of the ship is proportional to the square of its speed, so that \(a=-k v^{2}\).

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Vo 80 ft/sec 8=35 fence -100 30- 20 x