A particle moves on a circular path of radius r 0 8 m with a constant speed of 2 m s The velocity undergoes a vector change v from A to B Express the magnitude of v in terms of v and and divide it by the time interval t between A and B to obtain the magnitude of the average acceleration of the part...

The magnitude of the velocity at any point on the circular path is v 2 ms The magnitude of ...

A particle moves on a circular path of radius r = 0.8 m with a constant speed

Question:

A particle moves on a circular path of radius r = 0.8 m with a constant speed of 2 m/s. The velocity undergoes a vector change Δv from A to B. Express the magnitude of Δv in terms of v and Δθ and divide it by the time interval Δt between A and B to obtain the magnitude of the average acceleration of the particle for (a) Δθ = 30°, (b) Δθ = 15°, and (c) Δθ = 5°. In each case, determine the percentage difference from the instantaneous value of acceleration.