Is it possible to first evaluate OVT and then discount this to time 0 to give OV,
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Is it possible to first evaluate OVT and then discount this to time 0 to give OV, rather than discounting E[ST] and Var[ST] to time 0, and then evaluating OV? Would you anticipate that you would get the same answers either way that you did the calculation? Is OV the same as a discounted OVT? If not, what is the difference and why is there a difference? Test this numerically. Try a range of values of ST, K, r and T. Compare OV calculated by both approaches.
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Related Book For
Infrastructure Investment An Engineering Perspective
ISBN: 9781466576698
1st Edition
Authors: David G. Carmichael
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