A solution was prepared by dissolving 367 mg of K 3 Fe(CN) 6 (329.2 g/mol) in sufficient
Question:
A solution was prepared by dissolving 367 mg of K3Fe(CN)6 (329.2 g/mol) in sufficient water to give 750.0 mL. Calculate
(a) The molar analytical concentration of K3Fe(CN)6.
(b) The molar concentration of K+.
(c) The molar concentration of Fe(CN)63-.
(d) The weight/volume percentage of K3Fe(CN)6.
(e) The number of millimoles of K+ in 50.0 mL of this solution.
(f) The concentration of Fe(CN)63- in ppm.
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a The molar concentration of a solution is calculated by dividing the number of moles of solute by t...View the full answer
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Related Book For 
Fundamentals Of Analytical Chemistry
ISBN: 9780357450390
10th Edition
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
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