The iodide in a sample that also contained chloride was converted to iodate by treatment with an
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The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine:
The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate:
In the analysis of a 1.59-g sample, 0.0538 g of barium iodate was recovered. Express the results of this analysis as percent sodium iodide.
Transcribed Image Text:
3H,0 + 3Br, + I → 6Br + IO, + 6H+
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ANALYSIS AS PERCENT SODIUM IODIDE The reaction is represented as I 3Br 2 3H 2 O 6Br IO 3 ...View the full answer
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Related Book For
Fundamentals Of Analytical Chemistry
ISBN: 9780357450390
10th Edition
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
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