The phosphorus in a 0.3019-g sample was precipitated as the slightly soluble (NH₄)₃PO₄ . 12MoO₃. This precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess of Pb²⁺ resulted in the formation of 0.3192 g of PbMoO₄. Express the results of this analysis in terms of percent P₂O₅.