In water, O 2 (aq) is a strong base. If 100.0 mg of K 2 O(s) is
Question:
In water, O2–(aq) is a strong base. If 100.0 mg of K2O(s) is dissolved in 1.25 L of aqueous solution, what will be the pH of the solution?
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1 Write the balanced chemical equation When K2O dissolves in water it reacts with water to produce KOH The balanced chemical equation is K2Os H2Ol 2KOHaq 2 Calculate the moles of K2O We are given that 1000 mg of K2O is dissolved in 125 L of solution We can use the molar mass of K2O to convert milligrams to moles 1000 mg K2O 1 mol K2O9419 g K2O 000106 mol K2O 3 Calculate the moles of KOH From the balanced chemical equation we see that 1 mole of K2O produces 2 moles of KOH Therefore we have 000106 mol K2O 2 mol KOH1 mol K2O 000212 mol KOH 4 Calculate the concentration of KOH We are given that the solution is 125 L Therefore we can calculate the concentration of KOH as 000212 mol KOH 125 L 000169 M KOH 5 Write the dissociation equation for KOH KOH is a strong base so it dissociates completely in water to produce K ...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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