Question: You are given these three reducing agents: Zn(s), Sn 2+ (aq), and I (aq). Use data from Appendix D to determine which of them
You are given these three reducing agents: Zn(s), Sn2+(aq), and I–(aq). Use data from Appendix D to determine which of them can, under standard-state conditions in acidic solution, reduce
(a) Cr2O7 2–(aq) to Cr3+(aq).
(b) Cr3+(aq) to Cr2+(aq).
(c) SO42–(aq) to SO2(g).

TABLE D.1 Ground-State Electron Configurations Element Configuration Z Z 1 2 3 4 5 6 7 8 9 HIG&LUZONSUZ SE> 0 2 3 2 3 5 3 3 2 2 5 2 He 10 11 12 13 14 15 16 17 18 19 20 21 Sc 22 23 24 25 Mn Mg 26 27 28 Ni 29 30 31 32 33 34 35 36 Zn Ga Ge 1s 1s [He] 2s [He] 2s2 [He] 2s2p [He] 2s2p [He] 2s2p [He] 2s22p4 [He] 2s2p5 [He] 2s2p6 [Ne] 3s [Ne] 3s2 [Ne] 3s 3p [Ne] 3s23p [Ne] 3s3p [Ne] 3s23p4 [Ne] 3s3p5 37 Rb 38 Sr 39 Y 40 Zr 41 Nb 42 Mo 43 Tc 44 Ru 45 Rh 46 Pd 47 Ag 48 Cd 49 In 50 Sn 51 Sb 52 Te 53 I 54 Xe 55 Cs 56 Ba 57 La 58 Ce [Ar]3d4s 59 Pr [Ar]3d54s 60 Nd 61 Pm [Ar]3d4s [Ar]3d64s 62 Sm [Ar]3d4s 63 Eu [Ar] 3d845 64 Gd 66 Dy [Ar]3d04s 65 Tb [Ar]3d04s2 [Ar]3d04s4p [Ar]3d04s4p Ho 67 68 Er [Ar] 3d04s4p 69 Tm Yb [Ar]3d04s4p4 70 [Ar] 3d04s4p5 71 Lu [Ar]3d04s4p6 [Ne] 3s 3p6 [Ar] 4s Element [Ar] 4s [Ar]3d4s [Ar] 3d4s Configuration Z [Kr] 5s [Kr] 5s [kr] 4d5s [Kr] 4d5s [Kr] 4d45s [kr] 4d55s [Kr] 4d55s [Kr] 4d75s [Kr] 4d85s1 [Kr] 4d10 [Kr] 4d105s1 [Kr] 4d05s [kr] 4d05s5p [Kr] 4d05s25p [kr] 4d05s5p [kr] 4d05s25p4 [Xe] 6s [Xe] 5d6s [Xe] 4f6s [Xe] 4f6s [Xe] 4f46s2 [Xe] 4f6s2 [Xe] 4f6s2 [Xe] 4f76s2 [Xe] 4f75d6s [Xe] 4f%s2 [Xe] 4f106s2 [Xe] 4f6s NRNKERKR [Xe] 4f126s2 [Xe] 4f136s2 [Xe] 4f146s2 [Xe] 4f45d6s 72 Hf 73 Ta W 74 75 Re 76 Os 77 Element 78 79 80 81 82 83 84 85 86 87 Fr [Kr] 4d05s5p5 88 Ra [Kr] 4d05s5p6 89 Ac [Xe] 6s 90 Th 91 92 93 94 95 96 97 98 99 Ir Pt Au Hg TI Pb Bi Po At Rn Pa U Np Pu Am Cm Bk Cf Es 100 Fm 101 Md 102 No 103 Lr 104 Rf 105 Db 106 Sg Configuration [Xe] 4f45d6s [Xe] 4f145d6s [Xe] 4f145d46s2 [Xe] 4f145d56s2 [Xe] 4f145d6s2 [Xe] 4f45d6s [Xe] 4f45d6s [Xe] 4f145d106s1 [Xe] 4f145d106s2 [Xe] 4f145d6s26p* [Xe] 4f145d106s36p? [Xe] 4f145d16s?6p3 [Xe] 4f145d6s6p* [Xe] 4f145d16s26p5 [Xe] 4f145d106s26p6 [Rn] 7s [Rn] 7s [Rn] 6d7s [Rn] 6d7s [Rn] 5f26d7s [Rn] 5f6d7s [Rn] 5f46d7s2 [Rn] 5f67s [Rn] 5f77s [Rn] 5f76d7s [Rn] 5f97s2 [Rn] 5f107,2 [Rn] 5f117s2 [Rn] 5f27s [Rn] 5f137,2 [Rn] 5f147s2 Rn] 5f46d7s [Rn] 5f46d7s [Rn] 5f46d7s2 [Rn] 5f46d7s
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a Using the standard reduction potentials in Appendix D we can find the following halfreactions for ... View full answer
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