The reaction between a 1,2-ethanediamine solution of K 4 [Pb 9 ] and a toluene solution of
Question:
The reaction between a 1,2-ethanediamine solution of K4[Pb9] and a toluene solution of [Pt(PPh3)4] in the presence of crypt-222 leads to the formation of the platinum-centred Zintl ion [Pt@Pb12]2−, the 207Pb NMR spectrum of which consists of a pseudo-triplet (J207Pb195Pt = 3440 Hz).
(a) What is the role of the crypt-222 in the reaction?
(b) Sketch the appearance of the 207Pb NMR spectrum, paying attention to the relative intensities of the components of the triplet. Explain how this signal arises, and indicate on your diagram where the value of J207Pb195Pt is measured.
(c) The 195Pt NMR spectrum of [Pt@Pb12]2− is a nonbinomial multiplet. Explain the origins of the coupling pattern. What is the separation (in Hz) of any pair of adjacent lines in the multiplet?
Step by Step Answer:
a Role of crypt222 Crypt222 is a bifunctional ligand that can coordinate to both the potassium and p...View the full answer
