The reaction of InBr with an excess of HCBr₃ in 1,4-dioxane (C₄H₈O₂) leads to compound A which is an adduct of 1,4-dioxane and contains 21.4% In. During the reaction, the indium is oxidized. The ¹H NMR spectrum of A shows signals at δ 5.36 ppm (singlet) and δ 3.6 ppm (multiplet) in a ratio 1: 8. Treatment of A with two molar equivalents of InBr followed by addition of [Ph₄P]Br yields the salt B which contains 16.4% In and 34.2% Br. The ¹H NMR spectrum of B exhibits signals in the range δ 8.01–7.71 ppm and a singlet at δ 0.20 ppm with relative integrals of 60: 1. Suggest identities for A and B.