The reaction of RuCl 2 (PPh 3 )(dppb) with phen leads to the loss of PPh 3 and the formation of an octahedral complex, X The structure of dppb is as follows The solution 31 P 1 H NMR spectrum of a freshly made sample of X shows a singlet at 33 2 ppm The sample is left standing in the light for a fe...

The changes observed in the 31P1H NMR spectrum of complex X upon exposure to light and standing for a few hours can be rationalized by considering the ...

The reaction of [RuCl 2 (PPh 3 )(dppb)] with phen leads to the loss of PPh 3

Question:

The reaction of [RuCl₂(PPh₃)(dppb)] with phen leads to the loss of PPh₃ and the formation of an octahedral complex, X. The structure of dppb is as follows:

The solution ³¹P{¹H} NMR spectrum of a freshly made sample of X shows a singlet at δ 33.2 ppm. The sample is left standing in the light for a few hours, after which time the ³¹P{¹H} NMR spectrum is again recorded. The signal at δ 33.2 ppm has diminished in intensity, and two doublets at δ 44.7 and 32.4 ppm (relative integrals 1: 1, each signal with J = 31 Hz) have appeared. Rationalize these data.