The heat of formation of ammonia from its constituent elements is \(11030 \mathrm{cal} / \mathrm{mol}\) at \(300 \mathrm{~K}\). What will be its heat of formation at \(1273 \mathrm{~K}\) ?

We are given that \(C_{\mathrm{P}_{2}}=6.94-0.2 \times 10^{-3} T, C_{P_{\mathrm{N}_{2}}}=6.45+1.4 \times 10^{-3} T\) and \(C_{P_{\mathrm{NH}_{3}}}=\) \(6.2+7.8 \times 10^{-3} T-7.2 \times 10^{-6} T^{2}\).