A boost converter powers a 4- resistor and 1-mH inductor load. The input voltage is 60 V,

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A boost converter powers a 4-Ω resistor and 1-mH inductor load. The input voltage is 60 V, and the output load voltage is 80 V. If the on-time is 2 ms, we determine the following.

Using Equation 13.12, 80 60 = 1 (1-D), which gives the duty ratio D = 0.25. Therefore, Ton = 0.25 T, that

Equation 13.12,

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Introduction To Electrical Power And Power Electronics

ISBN: 9781466556607

1st Edition

Authors: Mukund R. Patel

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Question Posted: Dec 04, 2023 12:48 AM

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A boost converter powers a 4- resistor and 1-mH inductor load. The input voltage is 60 V,

Question:

Using Equation 13.12, 80 ÷ 60 = 1 ÷ (1-D), which gives the duty ratio D = 0.25. Therefore, Ton = 0.25 T, that is, 2 ms = 0.25 T, which gives T = 8 ms, where T = Ton + Toff Switching frequency = 1/T = 1/0.008 = 125 Hz. Output current = 80/4 = 20 A Input current = 20 (1 - 0.25) = 15 A.

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Introduction To Electrical Power And Power Electronics

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