A 2-kg disk is constrained horizontally but is free to move vertically. The disk is struck from below by a vertical jet of water. The speed and diameter of the water jet are \(10 \mathrm{~m} / \mathrm{s}\) and \(25 \mathrm{~mm}\) at the nozzle exit. Obtain a general expression for the speed of the water jet as a function of height, \(h\). Find the height to which the disk will rise and remain stationary.

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-M = 2 kg h - d = 25 mm Vo= 10 m/s 75 P4.93