The simplified lawn sprinkler shown rotates in the horizontal plane. At the center pivot, \(Q=15 \mathrm{~L} / \mathrm{min}\) of water enters vertically. Water discharges in the horizontal plane from each jet. If the pivot is frictionless, calculate the torque needed to keep the sprinkler from rotating. Neglecting the inertia of the sprinkler itself, calculate the angular acceleration that results when the torque is removed.

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d = 5 mm R=225 mm P4.130, P4.134