Refer to Exercise 7.5, where the number of unremovable defects, for each of \(n=45\) displays, has \(\bar{x}=\) 2.467 and \(s=3.057\) unremovable defects.

(a) Conduct a test of hypotheses with the intent of showing that the mean number of unremovable defects is less than 3.6. Take \(\alpha=0.025\).

(b) Based on your conclusion in part (a), what error could you have made? Explain in the context of the problem.

Data From Exercise 7.5

Transcribed Image Text:

7.5 The manufacture of large liquid crystal displays (LCD's) is difficult. Some defects are minor and can be removed; others are unremovable. The number of unremovable defects, for each of n = 45 displays (Courtesy of Shiyu Zhou) 1 0 5 3 0 7 6 0 5 0 9 1 0 8 6 0 0 6 0 10 0 6 0 0 0 1 5 1 0 5 0 02 0312 4 2 0 808 609 has x = 2.467 and s = 3.057 unremovable defects. What can one assert with 98% confidence about the maximum error if x = 2.467 is used as a point esti- mate of the true population mean number of unremov- able defects?