The rise of current in an inductive circuit having the time constant (tau) is given by [I=1-e^{-t

Question:

The rise of current in an inductive circuit having the time constant \(\tau\) is given by

\[I=1-e^{-t / \tau}\]

where \(t\) is the time measured from the instant the switch is closed, and \(I\) is the ratio of the current at time \(t\) to the full value of the current given by Ohm's law. Given the measurements

image text in transcribed

estimate the time constant of this circuit from the experimental results given. [Hint: Note that the relationship between \(\ln (1-I)\) and \(t\) is linear.]

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Probability And Statistics For Engineers

ISBN: 9780134435688

9th Global Edition

Authors: Richard Johnson, Irwin Miller, John Freund

Question Posted: