Question: For the harmonic oscillator [V(x) = (1/2)kx 2 ], the allowed energies are where = k/m is the classical frequency. Now suppose the spring

For the harmonic oscillator [V(x) = (1/2)kx2], the allowed energies are

En = (n + 1/2)w, (n = 0, 1, 2, ...),

where ω = √k/m is the classical frequency. Now suppose the spring constant increases slightly: k→ (1+∈)k. (Perhaps we cool the spring, so it becomes less flexible.)
(a) Find the exact new energies (trivial, in this case). Expand your formula as a power series in ϵ, up to second order.
(b) Now calculate the first-order perturbation in the energy, using Equation 7.9. What is H' here? Compare your result with part (a).

En = (n + 1/2)w, (n = 0, 1, 2, ...),

Step by Step Solution

3.35 Rating (161 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a b 3 En n hw w... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Introduction To Quantum Mechanics Questions!