Performing a variational calculation requires finding the minimum of the energy, as a function of the variational
Question:
Performing a variational calculation requires finding the minimum of the energy, as a function of the variational parameters. This is, in general, a very hard problem. However, if we choose the form of our trial wave function judiciously, we can develop an efficient algorithm. In particular, suppose we use a linear combination of functions ∅n (x):
where the Cn are the variational parameters. If the ∅n are an orthonormal set ((∅m|∅n) = δmn), but Ψ(x) is not necessarily normalized, then (H) is
where Hmn = (Φm|H|Φn) . Taking the derivative with respect to c* j (and setting the result equal to 0) gives
recognizable as the jth row in an eigenvalue problem:
The smallest eigenvalue of this matrix H gives a bound on the ground state energy and the corresponding eigenvector determines the best variational wave function of the form 8.88.
(a) Verify Equation 8.90.
(b) Now take the derivative of Equation 8.89 with respect to c j and show that you get a result redundant with Equation 8.90.
(c) Consider a particle in an infinite square well of width a, with a sloping floor:
Using a linear combination of the first ten stationary states of the infinite square well as the basis functions,
determine a bound for the ground state energy in the case V0 = 100ћ2/ma2. Make a plot of the optimized variational wave function.
Step by Step Answer:
Introduction To Quantum Mechanics
ISBN: 9781107189638
3rd Edition
Authors: David J. Griffiths, Darrell F. Schroeter