Given the only naturally occurring isotope of aluminum is Al-27, determine its mass from the periodic table.

Transcribed Image Text:

2 3 4 5 6 7 3 11 1 IA Li Na 19 37 Rb 55 87 Fr 4 2 IIA Be 12 Mg 20 38 56 Ba 88 Ra 3 IIIB 21 Sc 39 57 Y La 89 Ac Atomic number Symbol Metals Semimetals Nonmetals 4 IVB 22 Ti 40 Zr 5 VB 72 23 41 Nb 73 Hf Ta Ce 90 -1 Th -H 6 VIB 24 Cr 42 Mo 74 W 59 91 PERIODIC TABLE OF THE ELEMENTS 7 VIIB Pa 25 Mn 43 75 Re 60 P Pr Nd 92 8 VIII U 26 44 Fe Ru 76 61 Pm 93 9 VIII 104 105 106 107 108 109 110 Rf Db Sg Bh Hs Mt D Np 27 Co 45 Rh 77 Ir 62 Sm 94 10 VIII Pu 28 Ni 46 78 47 Pd Ag 63 11 IB 29 95 Cu 79 Au 111 64 Eu Gd Rg 96 Am Cm 12 IIB 30 Zn 48 Cd 80 Hg 112 Cn 65 97 Bk 13 IIIA 13 31 Ga Al 49 81 In 66 TI 113 Nh 98 Cf 6 14 15 16 IVA VA VIA 14 Si 32 Ge 50 82 Pb 114 67 99 E Es 15 33 As 51 83 Bi 115 Mc 68 8 16 34 Se 52 S Te 84 Po 116 Lv 69 17 VIIA 9 17 Cl 35 53 85 Br I At 117 70 Ts 100 101 102 Fm Md No 18 VIIIA 2 He 10 Ne 18 Ar 36 Kr 54 Xe 86 Rn 118 Og 71 Lu 103 Lr