Suppose that log(y0 follows a linear model with a linear form of heteroskedasticity. We write this as
Question:
Suppose that log(y0 follows a linear model with a linear form of heteroskedasticity. We write this as
so that, conditional on x, u has a normal distribution with mean (and median) zero but with variance h(x) that depends on x. Because Med(u|x) = 0, equation (9.48) holds: Med(y|0x) = exp(β0 + xβ).Further, using an extension of the result from Chapter 6, it can be shown that
(i) Given that h(x) can be any positive function, is it possible to conclude δE(y|x)δxj is the same sign as βj?
(ii) Suppose h(x) = δ0 + xδ (and ignore the problem that linear functions are not necessarily always positive). Show that a particular variable, say x1, can have a negative effect on Med(y|x) but a positive effect on E(y|x).
(iii) Consider the case covered in Section 6-4, in which h(x) = σ2. How would you predict y using an estimate of E(y|x)? How would you predict y using an estimate of Med(y|x)? Which prediction is always larger?
Step by Step Answer:
Introductory Econometrics A Modern Approach
ISBN: 9781337558860
7th Edition
Authors: Jeffrey Wooldridge