The maximum fluctuation of energy (mathrm{E}_{p}), during a cycle for a flywheel is (a) (Ileft(omega_{max }^{2}-omega_{min }^{2}
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The maximum fluctuation of energy \(\mathrm{E}_{p}\), during a cycle for a flywheel is
(a) \(I\left(\omega_{\max }^{2}-\omega_{\min }^{2}\right)\)
(b) \(\frac{1}{2} \cdot I \cdot \omega_{a v} \cdot\left(\omega_{\max }-\omega_{\min }\right)\)
(c) \(\frac{1}{2} \cdot I \cdot K_{e s} \cdot \omega_{a v}^{2}\)
(d) \(I \cdot \omega_{a v}^{2} \cdot \mathrm{K}_{e s}\)
(where \(I=\) Mass moment of inertia of the flywheel
\[ \begin{aligned} & \omega_{a v}=\text { Average rotational speed } \\ & K_{e s}=\text { Coefficient of fluctuation of speed) } \end{aligned} \]
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