The speed of driving shaft of a Hooke's joint of angle (19.5^{circ}) (given (sin 19.5^{circ}=.33, cos 19.5^{circ}=.94)

Question:

The speed of driving shaft of a Hooke's joint of angle \(19.5^{\circ}\) (given \(\sin 19.5^{\circ}=.33, \cos 19.5^{\circ}=.94\) ) is \(500 \mathrm{rpm}\). The maximum speed of the driven shaft is nearly

(a) \(168 \mathrm{rpm}\)

(b) \(444 \mathrm{rpm}\)

(c) \(471 \mathrm{rpm}\)

(d) \(531 \mathrm{rpm}\).

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: