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Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R= 10kn R=
Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R= 10kn R= 10kn C=0.002 F T RF2=90k +9V -9V Figure Q2(a) Calculate the overall effective gain of the circuit in decibels. Vo (6 marks) Determine the lower cut-off frequency and upper cut-off frequency. (6 marks)
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Income Tax Fundamentals 2013
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
31st Edition
1111972516, 978-1285586618, 1285586611, 978-1285613109, 978-1111972516
