Question: Assume that a random variable, x, is governed by the probability distribution (a version of the Lorentzian function) where x ranges from 6.000 to 6.000.

Assume that a random variable, x, is governed by the probability distribution (a version of the Lorentzian function)

f (x) = x2 +1'

where x ranges from ˆ’6.000 to 6.000.
(a) Find the mean value of x and its variance and standard deviation.
(b) Find the probability that x lies between Œ©xŒª ˆ’σx and Œ©xŒª +σx.

f (x) = x2 +1'

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