Find the function f (x,y) whose differential is df = (x + y) 1 dx + (x
Question:
Find the function f (x,y) whose differential is
df = (x + y)−1dx + (x + y)−1dy
and which has the value f(1,1) = 0. Do this by performing a line integral on a rectangular path from (1,1) to (x1,y1) where x1 > 0 and y1 > 0.
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Since the differential is exact We choose the path from ...View the full answer
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