Every countable set is a (lambda^{1})-null set. Use the Cantor ternary set (C) (see Problem 7.12) to
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Every countable set is a \(\lambda^{1}\)-null set. Use the Cantor ternary set \(C\) (see Problem 7.12) to illustrate that the converse is not true. What happens if we change \(\lambda^{1}\) to \(\lambda^{2}\) ?
Data from problem 7.12
![Cantor's ternary set. Let (X, )= ([0, 1], [0, 1] (R)), A=A [0,1], and set Co= [0, 1]. Remove the open middle](https://dsd5zvtm8ll6.cloudfront.net/images/question_images/1705/6/6/0/59265aa50b0074b21705660591454.jpg)
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