Question: Show that in the case of a binary system in which the orbit is circular of radius (r), the kinetic energy corresponds to half the

Show that in the case of a binary system in which the orbit is circular of radius $r$, the kinetic energy corresponds to half the absolute value of the potential energy. In other words, the total mechanical energy corresponds to $E=-\frac{1}{2} \frac{G m_{1} m_{2}}{r}$.

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