The G for ATP hydrolysis is 230.5 kJ mol 1 (27.3 kcal mol 1 ). In the
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The ΔG°´ for ATP hydrolysis is 230.5 kJ mol–1 (27.3 kcal mol–1). In the red blood cell at 37°C (310 K) the concentrations of ATP, ADP, and phosphate are 2.25, 0.25, and 1.65 mM, respectively. Show that these are not the equilibrium concentrations, and calculate the actual ΔG´ under these conditions. (2.3RT at 37°C is 5.93 kJ mol–1 [1.42 kcal mol–1].)
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The ATP hydrolysis reaction is 2 10 mM Mg ATP HO ADP phosphate First we calculate the equilibrium co...View the full answer
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