When an excess of 1,3-butadiene reacts with Cl 2 in chloroform solvent, two compounds, A and B,
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When an excess of 1,3-butadiene reacts with Cl2 in chloroform solvent, two compounds, A and B, both with the formula C4H6Cl2, are formed. Compound B reacts with more Cl2 to form compound C, C4H6Cl4, which proves to be a meso compound. Compound A reacts with more Cl2 to form both C and a diastereomer D. Propose structures for A, B, C, and D, and explain your reasoning.
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Assume that A and B are 12 and 14addition products Cl HCCHCHCH HC CHCHCH2 CCHCHCHCI 14addition produ...View the full answer
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