1. We have (f )i = i(cj xj ) = ci and (g)i = i(xjAjkxk) = (Aik...

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1. We have (∇f )i = ∂i(cj xj ) = ci and (∇g)i = ∂i(xjAjkxk) = (Aik + (A

)ik)xk.

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