The effective rate constant for a gaseous reaction that has a LindemannHinshelwood mechanism is 2.50 10
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The effective rate constant for a gaseous reaction that has a Lindemann–Hinshelwood mechanism is 2.50 × 10−4 s−1 at 1.30 kPa and 2.10 × 10−5 s−1 at 12 Pa. Calculate the rate constant for the activation step in the mechanism.
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The rate of the reaction is Rate k reciprocal h 250 104 s 1 exp3MPa13 kPa 26 ...View the full answer
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