Question: The effective rate constant for a gaseous reaction which has a LindemannHinshelwood mechanism is 2.50 10 4 s 1 at 1.30 kPa and 2.10

The effective rate constant for a gaseous reaction which has a Lindemann–Hinshelwood mechanism is 2.50 × 10⁻⁴ s⁻¹ at 1.30 kPa and 2.10 × 10⁻⁵ s⁻¹ at 12Pa. Calculate the rate constant for the activation step in the mechanism.

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